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The sum of $(6 a + 4 b - c + 3), (2 b - 3 c + 4), (11 b - 7 a + 2 c - 1)$ and $(2 c - 5 a - 6)$ is

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$4 a - 6 b + 2$

$(- 3 a + 14 b - 3 c + z)$

$(- 6 a + 17 b)$

$(- 6 a + 6 b + c - 4)$

answer is C.

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Detailed Solution

$\begin{array}{l} (6 a + 4 b - c + 3) + (2 b - 3 c + 4) + (11 b - 7 a + 2 c - 1) + (2 c - 5 a - 6) \\ = (6 a - 7 a - 5 a) + (4 b + 2 b + 11 b) + (- c - 3 c + 2 c + 2 c) + (3 + 4 - 1 - 6) \\ = - 6 a + 17 b + 0 + 0 = - 6 a + 17 b \end{array}$

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