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Q.

The sun’s angular diameter is measured to be $1920'' .$ The distance D of the sun from the earth is $1.496 \times 10^{11} m,$ the diameter of the sun is

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a

$9.31 \times 10^{3} m$

b

$1.39 \times 10^{9} m$

c

$3.26 \times 10^{6} m$

d

$8.32 \times 10^{4} m$

answer is B.

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Detailed Solution

Sun’s angular diameter $α = 1920''$

$= 1920 \times 4.85 \times 10^{- 6} r a d$

$= 9.31 \times 10^{- 3} r a d$

Sun’s diameter, $d = α D$

$= (9.31 \times 10^{- 3}) \times (1.496 \times 10^{11})$

$1.39 \times 10^{9} m$

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