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The surface area of a chalk box, whose length, breadth and height are 18 cm, 10 cm and 8 cm respectively is ____.

see full answer

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Detailed Solution

The surface area of a chalk box, whose length, breadth and height are 18 cm, 10 cm and 8 cm respectively is

808 c m 2

.
Given that, length of chalk box,

l = 18 c m

, breadth of chalk box,

b = 10 c m

and height of chalk box,

h = 8 c m

.
We know that, the total surface area of cuboid,

T = 2 (l b + b h + h l)

.
Substituting the value of length, breadth and height in the formula and simplify it,

T = 2 (18 c m × 10 c m + 10 c m × 8 c m + 8 c m × 18 c m)

T = 2 (180 c m 2 + 80 c m 2 + 144 c m 2)

T = 2 (404 c m 2)

T = 808 c m 2

Hence, the surface area of chalk box whose length, breadth and height are 18 cm, 10 cm and 8 cm respectively is

808 c m 2

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