Q.

The surface area of a cubiod is3328 m2  . Its dimensions are in the ratio 4: 3:2 , then the volume of the cuboid is 

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a

12288 m3

b

11288 m3

c

12882 m3

d

18388 m3

answer is A.

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Detailed Solution

Surface Area of a cuboid = 3328 m3
2(lb+bh+hl)=3328lb+bh+hl=1664m2(1)
Given: l:b:h=4:3:2
l=4x,b=3x,h=2x(4x)(3x)+(3x)(2x)+(2x)(4x)=166412x2+6x2+8x2=166426x2=1664x2=166426x2=83213;x2=64x=64;x=8l=4x=4(8)=32mb=3x=3(8)=24mh=2x=2(8)=16m Volume of cuboid =lbh=32×24×16=12288m3

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