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The surface charge density of a copper sphere is $σ$ .The electric field strength on the surface of sphere is

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$σ$

$\frac{σ}{2}$

$\frac{σ}{2 \in_{0}}$

$\frac{σ}{\in_{0}}$

answer is D.

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Detailed Solution

$σ = \frac{q}{4 π r^{2}}$

$E = \frac{q}{4 π r^{2} ε_{0}}$

$So E = \frac{q}{ε_{0}}$

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