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Q.

The surface of a metal is illuminated with the light of 400 nm wavelength. The kinetic energy of the ejected photoelectron is found to be 1.69 eV. The work function of the metal is

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a

3.09 eV

b

1.51 eV

c

1.41 eV

d

1.68 eV

answer is A.

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Detailed Solution

$E = \frac{hc}{λ} = \frac{1240}{400} = 3.1 eV$

Using Einstein's equation

$ϕ = E - K_{E} = 3.1 - 1.69 = 1.41 eV$

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