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Q.

The surface of water in a water tank of cross section area  750 cm2 on the top of a house is h m above the tap level. The speed of water coming out through the tap of cross section area  500 mm2  is  60 cm/s. At that instant, dhdt is  x×103 m/s. The value of x will be . 

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answer is 4.

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Detailed Solution

  Question Image
By continuity equation  A1V1=A2V2=  volume flow rate
Also, volume flow rate  =A1dhdt
So, volume flow rate  =A2V2=A1dhdtA2V2=A1dhdt
  500×106×0.60=750×104×dhdt  dhdt=4×103 m/x=4

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