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The surface tension of a liquid is 0.5 N/m. If a liquid film is formed on a ring of area 0.02 m2 then its surface energy will be

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a
0.01 Joule
b
0.02 Joule
c
0.03 Joule
d
0.04 Joule

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detailed solution

Correct option is B

Given,surface energy=surface tension×area=0.5×0.04=0.02J

Surface tension = 0.5N/m

area of the ring = 0.02 m2

The net area is =  2 × surface area since a ring has two open surfaces and the thin film will form on both of them.

area=2×0.02=0.04m2

surface energy=surface tension×area=0.5×0.04=0.02J

Hence the correct answer is 0.02J.

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