The surface tension of soap solution is $3.5\times {10}^{-2}{\mathrm{Nm}}^{-1}$. The amount of work done required to increase the radius of soap bubble from $10 \mathrm{cm}$ to $20 \mathrm{cm}$ is ______$\times {10}^{-4} \mathrm{J}$ (take  $\mathrm{\pi }=22/7)$