The surface tension of soap water is 0.04Nm^{- 1}. The excess of pressure inside a soap water bubble of diameter 10 mm is 

Given,

Surface tension $\mathrm{\sigma }=0.04\mathrm{N}/\mathrm{m}$

Diameter of the soap bubble D =10mm

$\mathrm{D}=10\mathrm{mm}\times {10}^{-3}=0.01\mathrm{m}$

Excess pressure inside a soap bubble

 $∆\mathrm{P}=\frac{8\times \mathrm{\sigma }}{\mathrm{D}}=\frac{8\times 0.04}{0.01}=32\mathrm{N}/{\mathrm{m}}^2=32\mathrm{Pa}.$

Hence the correct answer is 32Pa.