The symbol of helium atom is $H {e^{4}}_{2}$ . The number of neutrons present in $H e^{2 +}$ ion is

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answer is B.

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Detailed Solution

The symbol of helium atom is

H {e^{4}}_{2}

. The number of neutrons present in

H e^{2 +}

ion is 2.
To find the number of neutrons in the given symbol of an atom, we subtract the number of protons from the mass given in the symbol.
For He, atomic mass is 4, whereas atomic number is 2. Hence number of neutrons present in them is
=>

(4 - 2)

=> 2

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