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Q.

The system of linear equations x+y+z=2,2x+3y+2z=5,2x+3y+(a21)z=a+1 

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a

has a unique solution for |a|=3

b

has no solution when |a|=3

c

has infinitely many solutions for a=4

d

has infinitely many solutions for a=6

answer is B.

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Detailed Solution

The given system of linear equation can be written as [11123223a21][xyz]=[25a+1]

Now, let Δ=|11123223a21|=a23

Δ1=|211532a+13a21|=a2a+1

Δ2=|1212522a+1a21|=a23

Δ3=|11223523a+1|=a4

When |a|=3,Δ=0 But, Δ3=±3,Δ=0

System of linear equations is no solution when |a|=3

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