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The system of two masses 2kg and 3 kg shown in the figure is released from rest. The work done on 3 kg block by the force of gravity during first 2 seconds of its motion is $(g = 10 m s^{- 2})$

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Detailed Solution

$w = (m_{2} - m_{1}) g [\frac{1}{2} \frac{(m_{2} - m_{1}) g}{m_{1} + m_{2}} t^{2}]$

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