The system shown in the figure is in equilibrium at rest and the spring and string are massless. Now the string is cut. The acceleration of masses 2m and m just after the string is cut will be:

The correct option is A

g₂ upwards, g downwards

Initially, when the system is in equilibrium:

FBD of system:

Now, after the string is cut, T=0 i.e tension in string becomes zero instantaneously, while spring force will act at its initial value FSpring, due to inertia of spring.

FBD of individual blocks after string is cut, represented below: