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Q.

The table shows the distance covered in successive seconds by a body accelerated uniformly from rest

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What is the speed of the body at the end of 4th second?

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a

4  ms−1

b

14  ms−1

c

16  ms−1

d

8  ms−1

answer is D.

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Detailed Solution

From sn=u+a2(2n−1)

2=0+a2(2×1−1)

∴a=4  cms−1

Again from v=u+at=0+4×4=16  cms−1

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