The tangent and normal to the ellipse $8x^2+y^2=9$  at the point P (1,1) meet $\mathrm{x}-\mathrm{axis}$  at Q and R. Then area of  $\mathrm{\Delta PQR}$ In Sq Units is 

The equation of tangent at (1,1) to ellipse is 
$\begin{array}{l}8x+y=9\\ \Rightarrow Q=\left(\frac{9}{8},0\right)\end{array}$
And equation of normal is$\mathrm{x}-8\mathrm{y}=-7\Rightarrow \mathrm{R}=(-7,0)$
$\therefore$Area of  = $\mathrm{\Delta PQR}=\frac{65}{16} \mathrm{SQunits}.$