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Q.

The tangent at a point P on the hyperbola x2a2y2b2=1passes through the point (0, –b) and the normal at P passes through the point (2a2,0) then eccentricity of the hyperbola is

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a

2

b

3

c

3

d

2

answer is B.

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Detailed Solution

Given hyperbola x2a2-y2b2=1

Equation of tangent at Px1,y1 is xx1a2yy1b2=1 …..(1)  (1) passing through (0, -b) y1=b

Equation of normal at (x1,y1) is a2xx1+b2yy1=a2+b2

Equation of normal passing through (22a,0) then

a2(22a)x1+0=a2e2 x1=22ae2 Since the point (x1,y1) lies on hyperbola then 8a2a2e4-1=1 8e4=2 e4 =4 e=2

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