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The taxi fare in a city is as follows: for the first kilometer, the fare is 8 and for the subsequent distance it is 5 per km. Taking the distance covered as x km and total fare as Rs.y , A linear equation for this information is

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(0, 2), (1, 8), (2, 13)

(0, 3), (1, 6), (2, 13)

(0, 3), (1, 8), (2, 10)

(0, 3), (1, 8), (2, 13)

answer is D.

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Detailed Solution

Use the two-variable linear equation for this. The first-degree linear equation, also known as the polynomial equation

+ by + c = 0

, is nothing more than the geometric representation of a straight line.
Additionally, it is stated that the total fare is Rs. y and the total distance travelled is x km.
After the first kilometer, the distance travelled becomes

x - 1

.
At this rate, the first kilometer is

8

and each additional kilometer is

5

.
The fare amounts to

8 (1) + 5 (x - 1)

.
The simplified version of the above expression is

8 + 5 x - 5 = 5 x + 3

However, since the total fare is known to be y,

5 x + 3 = y, \Rightarrow 5 x - y + 3 = 0 \dots \dots . (1)

The necessary linear equation is Equation (1).
By putting

x = 0, 1, 2

we get

y

y = 3, 8, 13

Thus, the points

(0, 3), (1, 8), (2, 13)

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