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The taxi fare in a city is as follows: For the first kilometer, the fare is 8 and for the subsequent distance it is 5 per km. Taking the distance covered as x km and total fare as Rs. y, write a linear equation for this information and draw its graph.

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y = 2 x - 3

y = 3 x + 4

y = 5 x + 3

y = 5 x - 3

answer is C.

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Detailed Solution

The first kilometer of a taxi fare = Rs. 8
The cost of a taxi for the next distance = Rs. 5
Suppose, distance travelled overall = x
Overall fare = y
As per given question
For the

(x - 1)

kilometer, fare

= 5 (x - 1)

Therefore, the overall fare

y = 5 (x - 1) + 8

\Rightarrow y = 5 (x - 1) + 8

\Rightarrow y = 5 x - 5 + 8

\Rightarrow y = 5 x + 3

y = 5 x + 3 \dots (1)

[required linear equation]
Putting the value now

x = 0

in equation (1)

y = 5 \times 0 + 3

y = 0 + 3 = 3

y = 3

Placing a value on

x = 1

in equation (1)

y = 5 \times 1 + 3

y = 5 + 3 = 8

y = 8

Putting the value

x = 2

in equation (1)

y = 5 \times 2 + 3

y = 10 + 3 = 13

y = 13

Now we will get the points
Question Image

So, the graph from these points can be given as,

Hence, the points which is satisfy the equation

(0, 3), (1, 8), (2, 13)

.
So, the required linear equation is

y = 5 x + 3 .

Correct option is 3.

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The taxi fare in a city is as follows: For the first kilometer, the fare is 8 and for the subsequent distance it is 5 per km. Taking the distance covered as x km and total fare as Rs. y, write a linear equation for this information and draw its graph.

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