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Q.

The teacher instructed three students ‘A’, ‘B’ and ‘C’ respectively to prepare a 50% (mass by volume) solution of sodium hydroxide (NaOH). ‘A’ dissolved 50 g of NaOH in 100 mL of water, ‘B’ dissolved 50 g of NaOH in 100 g of water ‘C’ dissolved 50 g of NaOH in water to make 100 mL solution. Which of the following have made the desired solution?


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a

A

b

B

c

C

d

A, B and C are all equal 

answer is C.

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Detailed Solution

 Firstly we calculate mass by volume percentage for student ‘A’
Mass of solute (NaOH) = 50 g
Total volume of solution = mass of solute + mass of solvent 50 + 100
Mass by volume percentage =Mass of solutevolume of solution×100
50150×100
33.33%
Now we calculate mass by volume percentage for student ‘B’
Mass by volume percentage = Mass of solutevolume of solution ×100
According to question student B dissolved 50 g of NaOH in 100 g of water so it will give percentage mass by mass rather than mass by volume percentage.
Now  we calculate mass by volume percentage for student ‘C’
Mass of solute(NaOH) = 50 g Total volume of solution = 100 mL
Mass by volume percentage =  Mass of solutevolume of solution×100
 50100×100
 50%
So ‘C’ has made the desired solution because 50% (mass by volume) solution means 50 g of solute dissolved in 100 mL solution.
 
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