The temperature at which l0% aqueous solution (w/v) of glucose will exhibit the osmotic pressure of 14 bar is 

$\mathrm{\pi }=\frac{\mathrm{nRT}}{\mathrm{V}}\text{ or }\mathrm{T}=\frac{\mathrm{\pi V}}{\mathrm{nR}}$
l0% (w/v) aqueous solution of glucose means
10 g glucose is present in 100 mL of H₂O
$=\frac{14\times 100\times {10}^{-3}\times 180}{0.082\times 10}=307.3\mathrm{K}$