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The temperature at which oxygen molecules have the same root mean square speed as helium atoms have at 300 K is (atomic masses: He= 4 u and O = 16 u)

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300 K

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1200 K

answer is D.

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Detailed Solution

$\frac{3 R T}{32 g {mol}^{- 1}} = \frac{3 R (300 K)}{4 g {mol}^{- 1}}$ . This gives T= 2400 K.

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