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Q.

The temperature at which the average speed of oxygen molecules is double that of the same molecules at 0ºC is

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a

546 K

b

1092 K

c

277 K

d

1911ºC

answer is B.

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Detailed Solution

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Vavg=8RTπM V α T ⇒V12V1=273T 14=273T T=1092K

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