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Q.

The temperature coefficient of a reaction is 2.5. If its rate constant at $T_{1} K$ is $2.5 \times 10^{- 3} s^{- 1}$ , the rate constant at $T_{2} K$ in $s^{- 1}$ is $(T_{2} > T_{1})$

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a

$1.0 \times 10^{- 2}$

b

$6.25 \times 10^{- 2}$

c

$1.0 \times 10^{- 3}$

d

$6.25 \times 10^{- 3}$

answer is B.

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Detailed Solution

$\frac{K_{T + 10}}{K_{T}} = 2.5 \begin{aligned} k_{T + 10} & = k_{r} (2.5) \\ = (2.5 \times 10^{- 3}) (2.5) \\ = 6.25 \times 10^{- 3} \end{aligned}$

Therefore, the correct option is (B).

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The temperature coefficient of a reaction is 2.5. If its rate constant at T1 K is 2.5×10-3 s-1, the rate constant at T2 K in s-1 is T2>T1