The temperature coefficient of resistance for a wire is 0.00125/⁰C. At 300 K its resistance is 1 ohm. The temperature at which the resistance becomes 2 ohm is

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1100 K

1154 K

1400 K

1127 K

answer is D.

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Detailed Solution

$\begin{array}{l} \frac{R_{1}}{R_{2}} = \frac{(1 + α t_{1})}{(1 + α t_{2})} \Rightarrow \frac{1}{2} = \frac{(1 + 0.00125 \times 27)}{(1 + 0.00125 \times t)} \\ \Rightarrow t = 854^{0} C \Rightarrow T = 1127 K \end{array}$

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