The temperature coefficient of resistance of a wire is 0.00125 per 0C. At 300 K, its resistance is 1 ohm. This resistance of the wire will be 2 ohm at _________K

R1=R01+αt1⇒1=R0[1+0.00125×27]R2=R01+αt2⇒2=R01+0.00125×t2On solving we getT2=854∘C=1127K

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The temperature coefficient of resistance of a wire is 0.00125 per ⁰C. At 300 K, its resistance is 1 ohm. This resistance of the wire will be 2 ohm at _________K

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answer is 1127.

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Detailed Solution

$\begin{aligned} R_{1} = R_{0} (1 + {αt}_{1}) \Rightarrow 1 = R_{0} [1 + 0 .00125 \times 27] \\ R_{2} = R_{0} (1 + {αt}_{2}) \Rightarrow 2 = R_{0} [1 + 0 .00125 \times t_{2}] \end{aligned}$
On solving we get
$T_{2} = 854^{\circ} C = 1127 K$

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