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Q.

The temperature coefficient of resistance of a wire is 0.00125 per °C. At 300 K its resistance is 1 $Ω$ . The resistance of the wire will be 2 $Ω$ at

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a

1154 K

b

1100 K

c

1400 K

d

1127 K

answer is D.

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Detailed Solution

$1 = R_{0} (1 + 27 α)$

$2 = R_{0} (1 + α t) ∴ 1 + α t = 2 (1 + 27 α) \Rightarrow t = \frac{1 + 54 α}{α} = 54 + \frac{1}{α} = 854 ° C \Rightarrow T = 1127 K$

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