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Q.

The temperature coefficient of resistivity of material is  0.0004/K.When the temperature of the material is increased by 50°C , its resistivity increases by 2×10−8Ω m The initial resistivity of the material in Ω

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a

100×10−8

b

200×10−8

c

90×10−8

d

50×10−8

answer is C.

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Detailed Solution

Given that α=0.0004/K

Δt=50°C

ρt=ρ01+αt

ρ0+2×108=ρ0+ρ0×4×10−4×50ρ0=100×10−8Ω−m

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