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The temperature of 5 moles of a gas at constant volume is changed from 100°C to 120°C.The change in internal energy is 80J. The total heat capacity of the gas at constant volume will be in joule/kelvin is

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answer is B.

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Detailed Solution

$Δ T = (120 - 100) K = 20 K$

$Q_{V} = n C_{v} Δ T$

$\therefore$ Heat capacity = nC_V

$= \frac{Q_{V}}{Δ T}$

$= \frac{80}{20} J / K$

= 4 J/K

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