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Q.

The temperature of a gas is –50 °C . To what temperature the gas should be heated so that the rms speed is increased by 3 times?

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a

669 °C 

b

3097 K

c

223 K

d

3295 °C 

answer is C.

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Detailed Solution

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If speed increases by 3 times, fi nal speed will be 4 times

We know Vrms=3RTM

V1V2=T1T2

V14V1=T1T2

T2 = 16   T1 = 16 ( 273-50) = 3568 K
T2 = 3568 -273 = 3295°C

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