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Q.

The temperature of lower fixed point, and upper fixed point, on the Fahrenheit scale is ____oF and ____oF.


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Detailed Solution

Concept- The temperature of lower fixed point, and upper fixed point, on the Fahrenheit scale is 32oF and 212oF. The melting point of ice (the solid state of water) , which is equivalent to the lower fixed point, Question Image and the upper fixed point is defined as the boiling point of water and it is equal to Question Image. These temperatures will be converted from degrees Celsius to degrees Fahrenheit in this section. The formula: can be used to do this.
Question ImageWe shall address each component of our problem separately. Let's begin by resolving the first component.
(i) It is equivalent to the lowest fixed point Question Image. Let this temperature be denoted by ' Question Image ' in degree Celsius and ' Question Image ' in degrees Fahrenheit.
Now, we can apply the formula to convert any Celsius temperature to a Fahrenheit value. Here's how to go about it:
Question ImageNow, putting the value of ' Question Image ' in above equation and solving for ' Question Image ', we get:
Question ImageQuestion ImageAs a result, the temperature of the lower fixed point is Question Image(ii) The upper fixed point is equal to Question Image. Let this temperature be denoted by ' Question Image ' in degree Celsius and ' Question Image ' in degrees Fahrenheit.
 We can now apply the algorithm to convert any Celsius temperature to Fahrenheit. The way to do this is as follows:
Question ImageNow, putting the value of ' Question Image ' in above equation and solving for ' Question Image ', we get:
Question ImageQuestion ImageQuestion ImageAs a result, the temperature of the top fixed point is Question Image.
Hence, the temperature of (i) lower fixed point, and (ii) upper fixed point, on the Fahrenheit scale comes out to be Question Image and Question Image respectively.
Hence, the answer is 32,212 oF.
 
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The temperature of lower fixed point, and upper fixed point, on the Fahrenheit scale is ____oF and ____oF.