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Q.

The temperature of the cold junction of a thermocouple is 0°C and the temperature of hot junction is T°C. The e.m.f. is $e = (16 T - 0 .04 T^{2}) μV$
The inversion temperature T_i is

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a

200°C

b

400°C

c

100°C

d

300°C

answer is B.

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Detailed Solution

Given that e $= 16 T - 0 \cdot 04 T^{2}$
At temperature of inversion, e = 0
$∴ 16 T_{i} - 0 \cdot 04 T_{i}^{2} = 0$
or $T_{i} = \frac{16}{0 \cdot 04} = 400^{\circ} C$

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The temperature of the cold junction of a thermocouple is 0°C and the temperature of hot junction is T°C. The e.m.f. is e=16T−0.04T2μVThe inversion temperature Ti is