The temperature Vs time graph for two materials A & B has been plotted when the energy has been given to both at same rate. Initially both the materials are in solid state (below their Melting point) and have equal mass. Given $L_{f} =$ latent heat of fusion and $L_{V} =$ latent heat of vapourisation. Then

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$L_{v A} < L_{v B}$

Specific heat of A in solid state > specific heat of B in solid state

Specific heat of A in liquid state > specific heat of B in liquid state

$L_{f A} = L_{f B}$

answer is A, D.

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Detailed Solution

$d Q = m s d T \Rightarrow p d t = m s d T$

$\frac{d T}{d t} = \frac{P}{m s} \Rightarrow s l o p e = \frac{P}{m s} s \propto \frac{1}{s l o p e} s_{A} > s_{B} i n s o l i d s t a t e d Q = m L P d t = m L L \propto d t {(L_{f})}_{A} = {(L_{f})}_{B} a n d {(L_{v})}_{A} = {(L_{v})}_{B}$

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