The temporary hardness of a water sample is due to compound X. Boiling this sample converts X to compound Y. X and Y respectively, are

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$Ca ({HCO}_{3})_{2}$ and $Ca (OH)_{2}$

$Ca ({HCO}_{3})_{2}$ and $CaO$

$Mg ({HCO}_{3})_{2}$ and $Mg (OH)_{2}$

$Mg ({HCO}_{3})_{2}$ and $M g C O_{3}$

answer is D.

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Detailed Solution

The salts (bicarbonates)of magnesium and calcium are responsible for temporary the hardness of the water.
It can be removed simply by heating. Upon heating calcium bicarbonate, it decomposes into calcium carbonate, carbon dioxide and water

$Ca ({HCO}_{3})_{2} \to {CaCO}_{3} + {CO}_{2} ↑ + H_{2} O$

Upon heating magnesium bicarbonate, it decomposes into magnesium hydroxide, carbon dioxide and water

$Mg ({HCO}_{3})_{2} \to Mg (OH)_{2} + {CO}_{2} ↑ + H_{2} O$

${Mg(OH)}_{2}$ which is insoluble and can be removed by filtration to get soft water.

Hence the correct answer is (D).

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