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Q.

The term independent of x in the expansion of 112x+3x7x2+13x10 is

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a

10/38

b

-2/3

c

10/39

d

11/6

answer is A.

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Detailed Solution

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(r + 1)th term in the expansion of x2+13x10is

tr+1=10Crx210r13xr=10Cr13rx203r

We require terms containing x0,x and x7 in the expansion of  x2+13x10

For x0, set 203r=0. No value of r.

For, x1 set 203r=1. No value of r.

For, x-7 set 203r=-7r=9.

Thus, required coefficient is

3 10C9139=1038

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