Q.

The term independent of x in the expansion of 1x2+3x352x315x211,x0 is :

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

33200

b

39200

c

740

d

1150

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail

General term of 52x315x211 is = 11Cr52x311r15x2r

General term is  11Cr5211r15rx335r

Now, term independent of x

=1× coefficient of x0 in 52x315x211

1× coefficient of x2 in 52x315x211 + 3× coefficient of x3 in 52x315x211

for coefficient of x0 ,  335r=0 not possible, since r is non negative integer

for coefficient of x2   335r=2

                                       35=5rr=7

for coefficient of x3   335r=3

                                       36 = 5r not possible

So term independent of x is

(1)11C7524157=33200

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon