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The thickness of paper is $0.002 m$ and that of another paper is $0.008 m$ . Compare their sizes.

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Paper-1 is double thicker than paper-2.

Thickness of paper-1 is half the thickness of paper-2.

Thickness of paper-1 is one-fourth of the thickness of paper-2.

Paper-1 and paper-2 are both equally thick.

answer is C.

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Detailed Solution

Given that the thickness of paper 1

= 0.002 m

.
The thickness of paper 2

= 0.008 m

.
We must evaluate the thickness of the papers.

\frac{Thickness of paper 1}{Thickness of paper 2} = \frac{0.002}{0.008} = \frac{1}{4}

\Rightarrow

Thickness of paper 1

= \frac{1}{4}

\times

(Thickness of paper 2)
Hence, the thickness of paper-1 is one-fourth of the thickness of paper-2 is the right answer.
Hence, option 3 is correct.

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