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Q.

The third ionization energy is least for :

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a

aluminum

b

boron

c

phosphorus

d

nitrogen

answer is D.

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Detailed Solution

The third ionization energy is least for boron.

Due to its charge density, boron has the highest third ionization energy, and after losing three electrons, it transitions into a noble gas state. As a group grows smaller, ionization energy falls.

Hence, option D is correct.

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