The thread and a heavy block rest on a surface. A particle P of mass 1kg moving upward with a velocity of $10 m s^{- 1}$ collide with the lighter block and sticks to it. The speed of the bigger block just after the string is taut will be ( Take $g = 10 {ms}^{- 2}$ , m = 1kg and M = 3kg)

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$5 m s^{- 1}$

$2.5 m s^{- 1}$

$2 m s^{- 1}$

$4 m s^{- 1}$

answer is D.

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Detailed Solution

Let speed of P and m after collision is u, $2 u = 1 \times 10$

$u = 5$

Just before string taut P and m will move down with $5 m s^{- 1} .$ After string taut m, M and P move with v.

$2 \times 5 = 5 v$

$v = 2 m s^{- 1}$

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