Q.

The three different irrational numbers between the rational numbers 5 7 and 9 11  are:


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a

0.74074007400074000074…….
0.7240724007240007250000……..
0.808008000800008….

b

0.74074007400074000074…….
0.7260726007260007260000……..
0.808008000800008….

c

0.74074007400074000074…….
0.7340734007340007350000……..
0.808008000800008….

d

0.74074007400074000074…….
0.7240724007240007250000……..
0.606006000600006….  

answer is A.

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Detailed Solution

Given the numbers are 5 7 and 9 11  .
Decimal expansion of Irrational numbers:
The decimal expansion of irrational numbers is non terminating non-recurring (repeating).
Divide 5 7   and 9 11   to find irrational numbers:
7 0.714285 50 49 -- 10 7 -- 30 28 -- 20 14 -- 60 56 -- 40 35 -- 5 --  
Thus ,
5 7 =0. 714285 ¯  .
And
1 1 0.8181... 90 88 -- 20 11 -- 90 88 -- 90 88 -- 2 --  ------
Thus, 9 11 =0. 81 ¯  .
That means the required irrational number will lie between 0. 714285 ¯   and 0. 81 ¯  .
Now, write the three irrational number between 0. 714285 ¯  and 0. 81 ¯  are:
0.74074007400074000074…….
0.7240724007240007250000……..
0.808008000800008….
Hence, the three different irrational numbers between the rational numbers 5 7   and 9 11   are:
0.74074007400074000074…….
0.7240724007240007250000……..
0.808008000800008….
Therefore, the correct option is 1.
 
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