The three stable isotopes of neon ${N_{e}}^{20}, {N_{e}}^{21}$ and ${N_{e}}^{22}$ have respective abundances of $90.51 %, 0.27 %$ and $9.22 % .$ The atomic masses of the three isotopes are $19.99 u, 20.99 u$ and $21.99 u$ respectively. Obtain the average atomic mass of neon.

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$32.184$

$30.184$

$25.184$

$20.1771$

answer is D.

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Detailed Solution

Average atomic mass of neon

$A_{n e o n} = \frac{p_{1} A_{1} + p_{2} A_{2} + p_{3} A_{3}}{p_{1} + p_{2} + p_{3}} A_{n e o n} = \frac{90.51 \times 19.99 + 0.27 \times 20.99 + 9.22 \times 21.99}{100} A_{n e o n} = \frac{1809.29 + 5.6673 + 202.75}{100} = 20.1771$

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