Q.

The three vertices of a parallelogram taken in order are (−1,0), (3,1)and (2,2)respectively. Find the coordinate of the fourth vertex.


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a

(1,2)

b

(-2,1)

c

(1,-2)

d

(-1,-2) 

answer is B.

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Detailed Solution

Let A(-1, 0), B(3, 1), C(2, 2) and D(x, y) be the vertices of a parallelogram ABCD taken in order. Since, the diagonals of a parallelogram bisect each other.
Then, Coordinates of the mid-point of AC=Coordinates of the mid-point of BD
Then, using the formula, (-1+22,0+22)=(3+x2,1+y2)
Or, 12,1=(3+x2,1+y2)
Comparing we get, 3+x2=12 and 1+y2=1
x=−2andy=1
Hence, the fourth vertex of the parallelogram is (-2, 1)

hence option (2) is the correct option.
 
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