The three vessels shown in figure have same base area. Equal volumes of a liquid are poured in the three vessels. The Force on the base will be                              

Given that the three vessels A, B and C are filled with same liquid of same volume

$\text{m}={\rho }_l\text{v}$

All three vessels have same base area but different shapes as shown.

We know $\text{P}=\frac{\text{F}}{\text{A}}\times \frac{\text{h}}{\text{h}}\Rightarrow \frac{\text{mgh}}{\text{v}}=\rho \text{gh}$

The  pressure of liquid coloumn depends on ${\text{h}}_{\text{1}}\text{and}{\rho }_{\text{1}}\text{and}\text{g}$ .

Here we observe the height of liquid in three vessel is not same

${\text{h}}_{\text{A}}<{\text{h}}_{\text{B}}<{\text{h}}_{\text{C}}$

So the ${\text{P}}_{\text{A}}<{\text{P}}_{\text{B}}<{\text{P}}_{\text{C}}$

We get pressure in vessel C is maximum.