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Q.

The threshold frequency of a metal is  1×1015s1       . The ratio of the maximum kinetic energies of the photoelectrons when the metal is irradiated with radiations of frequencies  1.5×1015s1 and  2.0×1015s1 respectively would be

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a

4 : 3

b

1 : 2

c

2 : 1

d

3 :4

answer is C.

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Detailed Solution

(KE)1(KE)2=v1v0v2v0=(1.5×10151×1015)(2.0×10151×1015)=12

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