Q.

The threshold wavelength for certain metal is λ0. When a light of wavelength λ0/2 is incident on it, the maximum velocity of photoelectrons is 106m/s. If the wavelength of the incident radiation is reduced to λ0/5, then the maximum velocity of the photo-electrons in m/s will be     

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a

4×106

b

2.5×106

c

5×106

d

2×106

answer is D.

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Detailed Solution

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ϕ=hcλ0 for wavelength λ02  =2ϕ  for λ05 =5ϕ

2ϕϕ=K1

5ϕϕ=K2

K1K2=14 v1v2=12

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