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Q.

The time – period of a particle undergoing S.H.M. is 16 sec. It starts its motion from the mean position. After 2 sec, its velocity is 0.4 m/s. The amplitude in cm.

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Detailed Solution

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T=16sec,t=2sec,V=0.4m/sy=asinωt     v=aωcosωt0.4=a(2π16)cos(2π16)×20.4=a×2π16×12a=1.44 m

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