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The time in seconds required to produce a potential difference of 20V across a capacitor of 1000μF when it is charged at the steady rate of 200μC /s is

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150

100

200

answer is B.

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Detailed Solution

$Q = CV = 1000 \times 10^{- 6} \times 20 = 20000 μC$
For $200 μ {Cs}^{- 1} \to t = ? t = \frac{20000}{200} = 100 \sec$

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