Q.

The time period of a simple pendulum is given by  T=2πlg. The measured value of the length of pendulum  is 10cm known to a 1 mm accurancy. The time for 200 oscillations of the pendulum is found to be 100 second using a clock of 1 s resolution. The percentage accuracy in the determination of ‘g’ using this pendulum is ‘x’. The value of ‘x’ to the nearest integer is 

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a

2%

b

3%

c

5%

d

4% 

answer is B.

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Detailed Solution

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T=2πl/g 
2ΔTT×100=Δll×100+Δgg×100 
So error in calculation of g in error in T = 2% & error in length = 1% 
So total = 3%

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