Q.

The time t, of a complete oscillation of a simple pendulum of length ‘l’ is given by the equation T=2πlg where ‘g’ is a gravitational constant find approximate percentage error in ‘T’ when the percentage of error in ‘l’ is 1%.

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answer is 1.

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Detailed Solution

Given time period of simple pendulum

t=2πlg,δll×100=1

logt=log2πgl=log(2π)g+12logl

Take differential on both sides 

Δtt12Δll Δtt×100

=12Δll×100=12(1)12 Δtt×10012

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