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The top of a water tank is open to air and its water level is maintained. It is giving out 0.74 m³ water per minute through a circular opening of 2 cm radius in its wall. The depth (in m) of the centre of the opening from the level of water in the tank is closed to _________ $\times$

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answer is 48.

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Detailed Solution

From the question,

Outflow volume equals inflow volume

$\frac{0.74}{60} = π \times 4 \times 10^{- 4} \times \sqrt{2 g h}$

$\sqrt{2 g h} = \frac{74 \times 100}{240 π}$

$2 g h = \frac{740 \times 740}{24 \times 24 \times π^{2}}$

$2 g h = \frac{74 \times 74}{2 \times 24 \times 24} h \approx 4.8 m$

Hence the correct answer is 4.8m.

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